Question

решите уравнение:
x^3+6x^2=4x+24

Answer 1

$x^3+6x^2=4x+24\x^3+6x^2-4x-24=0\x^2(x+6)-4(x+6)=0\(x^2-4)(x+6)=0\(x-2)(x+2)(x+6)=0\\1);x-2=0 qquad 2)x+2=0 qquad 3)x+6=0\x_1=2; qquad qquad quad x_2=-2 qquad quad x_3=-6$