Question

Помогите Пожалуйста!!!!!! Срочно!!!!

Answer 1

((x(3x+9)-3(x-1))/(x²-х))*((х²-х)/(3х+3))=((3х²+9х-3х+3)/(х²-х))*((х²-х)/(3(х+1))= ((3х²+6х+3)/(х²-х))*((х²-х)/(3(х+1))= (3(х²+2х+1)/(х²-х))*((х²-х)/(3(х+1))= (3(х+1)²/(х²-х))*((х²-х)/(3(х+1))=х+1

Answer 2

$( frac{3x+9}{x^2-1}- frac{3}{x^2+x} ): frac{3x+3}{x^2-x}= ( frac{3x+9}{(x-1)(x+1)}- frac{3}{x(x+1)} ): frac{3x+3}{x^2-x}= \ ( frac{3x^2+9x}{x(x-1)(x+1)}- frac{3x-3}{x(x+1)(x-1)} ): frac{3x+3}{x^2-x}= frac{3x^2+9x-3x+3}{x(x-1)(x+1)} : frac{3x+3}{x^2-x}= \ frac{3x^2+6x+3}{x(x-1)(x+1)} : frac{3x+3}{x^2-x}= frac{3(x-1)^2}{x(x-1)(x+1)} * frac{x(x-1)}{3(x+1)}= frac{(x-1)^2}{(x+1)^2}$