Question

169 срочно!!!!!!!!!!!!!!! пж

Answer 1

2) (√a+√b)/(a√a+b√b) * (a√a-b√b)/(a√a-b√b) = (a²-b√ab+a√ab-b²)/(a³-b³)
4) (a-√3a+3)/(a√a+3√3) * (a√a-3√3)/(a√a-3√3) = (a-√3a+3)(a√a-3√3)/(a³-27)
5) (2√10-5)/(4-√10) * (4+√10)/(4+√10) = (2√10-5)(4+√10)/6