Question

Сколько грамм Al содержится в 100 граммах солей: 1)AlBr3 2)Al(NO3)3 3)Al2(SO4)3 4)AlPO4 5)Al2S3

Answer 1

1) m(Al)=100g*W(Al)
W(Al)=$frac{Ar(Al)}{Mr( AlBr_{3}) }$ = $frac{27}{267}$ = 0.101
m(Al)=100g*0.101=10.1g
2) m(Al)=100g*W(Al)
W(Al)=$frac{Al}{Mr(Al(NO_{3}) _{3}) }$=$frac{27}{213}$≈0.127
m(Al)=100g*0.127=12.7g
3) m(Al)=100g*W(Al)
W(Al)=Mr(Al)/Mr(Al2(SO4)3)=54/342≈0.158
m(Al)=100g*0.158=15.8g
4) m(Al)=100g*W(Al)
W(Al)=Ar(Al)/Mr(AlPO4)=27/122≈0.221
m(Al)=100g*0.221=22.1g
5)m(Al)=100g*W(Al)
W(Al)=Mr(Al)/Mr(Al2S3)=54/150=0.36
m(Al)=100g*0.36=36g.