Question

решите уравнение x(x^2+4x+4)=3(x+2)

Answer 1

Х( х^2 + 4х + 4 ) = 3( Х + 2 )
Х( Х + 2 )^2 - 3( Х + 2 ) = 0
( Х + 2)( х( Х + 2 ) - 3 ) = 0
Х + 2 = 0
Х = - 2
Х( Х + 2 ) - 3 = 0
Х^2 + 2х - 3 = 0
D = 4 + 12 = 16 = 4^2
X1 = ( - 2 + 4 ) : 2 = 1
X2 = ( - 2 - 4 ) : 2 = - 3
Ответ - 2 ; 1 ; - 3