Question

log 2 (8) -log2 (3) +log2 (12)

Answer 1

log2(8/3*12)=log2(32) =log2(2^5)=5

Answer 2

$log_{2} 8- log_{2} 3+ log_{2} 12= log_{2} ( frac{8}{3}*12)= log_{2}32= log_{2}2^5=5$

P.S.

$log_{a} b- log_{a}c= log_{a} frac{b}{c}$

$log_{a} b+ log_{a}c= log_{a} (bc)$

Answer 3

спасибо большое