Question

помагите пожалуйста номер 97

Answer 1

$16a^4=(4a^2)^2\25m^4n^2=(5m^2n)^2\frac{16}{81}x^8y^4=(frac{4}{9}x^4y^2)^2\frac{144}{225}a^{10}b^4=(frac{12}{15}a^5b^2)^2=(frac{12}{15}a^5b^2)^2=(frac{4}{5}a^5b^2)^2=(0,8a^5b^2)^2\0,64m^4p^2=(0,8m^2p)^2\0,0289frac{a^4}{b^6}=(0,17frac{a^2}{b^3})^2$