Question

буква б) и в)
под буквой а) не надо

Answer 1

б) (3/11)*(4(7/9)-3(5/9))=(3/11)*1(2/9)=(3*11)/(11*9)=1/3
в) (3/5)*(3(2/9)+6(7/9))=(3/5)*10=(3*10)/5=3*2=6

Answer 2

б)
43/9×3/11-32/9×3/11=43/3×1/11-32/3×1/11= 43/33-32/33= 11/33=1/3
в) =29/9×3/5+3/5×61/9= 29/3×1/5+1/5×61/3= 29/15+61/15= 90/15=6