Question

(8x+1)(2x-3)-(4x-2)^2=1 решить уравнение

Answer 1

(8x+1)(2x-3)-(4x-2)²=1
16x²-24x+2x-3-(16x²-16x+4)=1
16x²-22x-3-16x²+16x-4-1=0
-6x-8=0
-6x=8/:(-6)
x=-8/6
x=-4/3