Question

2arcsin(-1/2)+arctg(-1)+arccos^2/2

Answer 1

$2arcsin(-frac{1}{2})+arctg(-1)+arccosfrac{sqrt2}{2}=\\=-2arcsinfrac{1}{2}-arctg1+frac{pi}{4}=\\=-2cdot frac{pi}{6}-frac{pi}{4}+frac{pi}{4}=-frac{pi}{3}$