Question

математика срочно ,.........

Answer 1

$displaystyle frac{log_2 4+log_2 sqrt{10} }{log_220+3log_22} = frac{log_2 2^2+log_2 10^{ frac{1}{2} }}{log_2 2cdot 10+3log_22} = frac{2+ frac{1}{2}log_210 }{1+log_210+3} =\\= frac{ frac{4+log_210}{2} }{4+log_210} = frac{1}{2}$