Question

Сократите дробь
$frac{(-9a ^{4}b ^{3}) ^{3} * (27a ^{3} b ^{9} ) ^{2} }{(-3a ^{2}b ^{3}) ^{9} }$

Answer 1

(-9а^4*б^3)^3*(27а^3*б^9)^2/(-3а^2*б^3)^9=
(9а^4=3а^2*3а^2, вынесу 3а^2 за скобки)
3^3*а^6(-3а^2*б^3)^3*(27а^3*б^9)^2/(-3а^2*б^3)^3*(-3а^2*б^3)^6=;
27а^6*27^2*а^6*б^18/-3^6*а^12*б^18=;
3^3*а^6*3^6*а^6/-3^6*а^12=;
3^3*а^12/-а^12= -27.