Question

(-3x^3y - 2x^4) : x^2 - (5xy^2 - y^3) : у^2 при х=-1, при у=2.

Answer 1

$displaystyle (-3x^{3y}-2x^{4}):x^{2}-(5xy^{2}-y^{3}):y^{2}= -3x^{3y-2}-2x^{2}-5x+y; \ \ npu:x=-1;y=2 \ \ -3x^{3y-2}-2x^{2}-5x+y=-3(-1)^{6-2}-2(-1)^{2}-5(-1)+2= \ \ =-3-2+5+2=2;$