Question

$frac{7-7a^2}{2a^3+2}=frac{5x}{10a^{2}-10a+10}$

Некто не поможет?

Answer 1

$dfrac{7-7a^2}{2a^3+2}=dfrac{5a}{10a^{2}-10a+10}\ dfrac{7(1-a^2)}{2(a+1)(a^2-a+1)}=dfrac{a}{2(a^{2}-a+1)}\ dfrac{7(1-a)}{2(a^2-a+1)}=dfrac{a}{2(a^{2}-a+1)}\ 7-7a=a\ a=frac78$