Question

$(sin alpha+cos alpha)^{2} + (sin alpha - cos alpha)^{2}-2$ упростить

Answer 1

$(sin alpha+cos alpha)^{2} + (sin alpha - cos alpha)^{2}-2=2(sin^2alpha+cos^2alpha)-2=0$

Answer 2

sin^2a+2sina*cosa+cos^2a+sin^2a-2sina*cosa+cos^2a-2=1+1-2=0

+2sina*cosa-2sina*cosa =0

sin^2a+cos^2=1