Question

2(х-2у)=х-8у 5(х+у)=2(х-у)+10

Answer 1

2(х-2у)=х-8у

2х-4у=х-8у

2х-х=4у-8у

х=-4у

 

5(х+у)=2(х-у)+10

5х+5у=2х-2у+10

5х-2х+5у+2у=10

3х+7у=10

подставляем х=-4у

3(-4у)+7у=10

-12у+7у=10

-5у=10

у=-2

х=-4*(-2)

х=8