Question

Найдите корни уравнения 3)7+2x^2=2(x+1)(x+3)

Answer 1

7 + 2х^2 = 2( Х + 1 )( Х + 3 )
( Х + 1 )( Х + 3 ) = х^2 + 3х + Х + 3 = х^2 + 4х + 3
7 + 2х^2 = 2( х^2 + 4х + 3 )
7 + 2х^2 = 2х^2 + 8х + 6
7 = 8х + 6
8х = 1
Х = 1/8
Х = 0,125

Answer 2

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