Question

Помогите сделать, срочно

Answer 1

$(x^2)^3=x^6 \ \ (-a^3)^2=a^6 \ \ ( frac{1}{4}y^3)^2= frac{1}{16}y^6 \ \ (-0,2c^2)^3= -0,008c^6 \ \ (frac{b^3}{f^2})^4= frac{b^{12}}{f^8} \ \ (n^{k+1})^3=n^{3k+3}$