Question

3у+(4-2у)=6 и 5(х+3)=27+3х 

Answer 1

1) 3у+(4-2у)=6

3у+4-2у=6

у+4=6
у=6-4 

у=2

 

2) 5(х+3)=27+3х
5х+15=27+3х
2х=12
х=12:2
х=6