Question

ПОМОГИТЕ СРОЧНО ПОЖАЛУЙСТА

Answer 1

x≠0
$x^{x ^{2/3} } = x^{x/2}$
$x^{2/3} =x/2$
$x=x sqrt{2x} /4$
4x=x√(2x)
x>0
x∈(0;∞)
4x-x√(2x)=0
x(4-√2x)=0
x=0 не удов усл
√(2x)=4
2x=16
x=8

Answer 2

$x^{ sqrt[3]{ x^{2} } } =( sqrt{x} ) ^{x}$
ОДЗ: 
$left { {{x geq 0} atop {x neq 0}} right., = textgreater x textgreater 0$
$x^{ sqrt[3]{ x^{2} } } = (x^{ frac{1}{2} } ) ^{x}$
$x^{ sqrt[3]{ x^{2} } } = x^{ frac{1}{2}*x }$
$sqrt[3]{ x^{2} } = frac{1}{2}*x$
$( sqrt[3]{ x^{2} } ) ^{3} =( frac{x}{2} ) ^{3}$
$x^{2} = frac{ x^{3} }{8}$
$frac{8 x^{2} - x^{3} }{ x^{3} } =0$
$left { {{8 x^{2} - x^{3} =0} atop { x^{3} neq 0}} right. , left { {{ x^{2} *(8-x)=0} atop {x neq 0}} right. = textgreater x=8$