Question

Вычислите массовую долю элементов в соединениях H2SO4

Answer 1

М(H2SO4) = 1*2 + 32 + 16*4 = 98

W(H) = Ar(H) *n / M(H2SO4) *100% = 1*2 / 98 *100% = 2%

W(S) = Ar(S) *n / M(H2SO4) * 100% = 32*1 / 98 *100% = 33%

W(O) = Ar(O) *n / M(H2SO4) *100% = 16*4 / 98 *100% = 65%