Question

Решите систему уравнений
2x-y=-1
y2-4x-2=0

Answer 1

{2x-y=-1
{y²-4x-2=0

x=(y-1)/2

y²-4(y-1)/2-2=0
y²-2y+2-2=0
y²-2y=0
y(y-2)=0
y1=0  => x1=(y-1)/2=-1/2
y2=2  = > x2=(2-1)/2=1/2

Отвее: (-1,2 ; 0) (1/2; 2)