Question

Помогите решить 3 номер

Answer 1

{2^x*3^-y=1152
{log(√5)(x+y)=2⇒x+y=5⇒x=5-y
x+y>0
2^(5-y)*3^-y=1152
32/6^y=1152
6^y=32/1152
6^y=1/36
y=-2
x=5+2=7
(7;-2)

Answer 2

{2^x*3^-y=1152
{log(√5)(x+y)=2⇒x+y=5⇒x=5-y
x+y>0
2^(5-y)*3^-y=1152
32/6^y=1152
6^y=32/1152
6^y=1/36
y=-2
x=5+2=7
7;-2