Question

Логарифмы...Упростите выражения lg b/lg a + 2/log b a -log a b^3=

Answer 1

lgb/lga+log(b)b²/log(b)a-log(a)b³=log(a)b+log(a)b²-log(a)b³=
=log(a)(b*b²/b³)=log(a)1=0