Question

(x-2)^2-4(x^2-4)+64=0

Answer 1

х^2-4х+4-4х^2+16+64=0
-3х^2-4х+80=0
3х^2+4х-80=0
Д=16+4*3*84=1024
х1=-4+32/6=28/6=14/3=4 2/3
х2=-4-32/6=-36/6=-6