Question

Разложите на множители k⁶n⁴-k³n²; 42a³b⁴-12abc; 3b+12-ab-4a

Answer 1

k^3n^2(k^3n^2-1)
6ab(7a^2b^3-2c)
(3-a)(b+4)

Answer 2

k⁶n⁴-k³n² = k³n² (k³n²-1) ;
42a³b⁴-12abc = 6ab (7a²b³-2c) ;
3b+12-ab-4a = 3(b+4)-a(b+4)=(3-a)(b+4).