Question

найди корень уравнения:с+4/6 = 3с-2/7

Answer 1

$c+frac{4}{6}$ = $3c-frac{2}{7}$

 

$c+frac{2}{3}=3c-frac{2}{7}$

$frac{20}{21}-2c=0$

 

$frac{1}{3}(3c+2)=frac{1}{7}(21c-2)$

$c=frac{10}{21}$