Question

Решите уравнение.
a)-8(x+6)=0;
б)-y(y-3)=0;
в)3(z+2)(z-4)=0.

Answer 1

a) -8x-48=0
-8x=48:(-8)
x=-6
б) -y^2-3y=0
-y*(y-3)=0
y1=0; y2=3
в)(z+2)*(z-4)
z+2=0
z-4=0
z1=-2; z2=4
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