Question

1) (3/7)^(3x-7)=(7/3)^(7x-3)
2) 3^x*(1/3)^(x-3)=(1/27)^x

Answer 1

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Answer 2

http://znanija.com/task/21316512

Answer 3

( 3/7 ) ^ ( 3х - 7 ) = ( 7/3 ) ^ ( 7х - 3 )
( 3/7 ) ^ ( 3х - 7 ) = ( 3/7 ) ^ ( 3 - 7х )
3х - 7 = 3 - 7х
10х = 10
Х = 1
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3^х•( 1/3 )^( Х - 3 ) = ( 1/27 ) ^ Х
3^х • 3^( 3 - Х ) = 3 ^ ( - 3х )
3 ^ ( Х + 3 - Х ) = 3 ^ ( - 3х )
3 ^ 3 = 3 ^ ( - 3х )
3 = - 3х
Х = - 1

Answer 4

http://znanija.com/task/21316512