Question

дано mAL=21.6г найти VH2

Answer 1

2Al + 6HCl = 2AlCl3 + 3H2
n(Al)=m/M=21,6/27=0,8
n(H2)=3/2 n(Al) =1,5*n(Al)=1,2
V(H2)=n(H2)*Vm=1,2*22,4=26,88л

Answer 2

спасибо