Question

помогите!!! 3 задание

Answer 1

$1)quad frac{4}{x+5} - frac{3}{x-1} = frac{36}{x^2+4x-5}-1\\x^2+4x-5=(x+5)(x-1)\\frac{4(x-1)-3(x+5)-36+x^2+4x-5}{(x+5)(x-1)}=0\\frac{4x-4-3x-15-36+x^2+4x-5}{(x+5)(x-1)} =0\\ frac{x^2+5x-60}{(x+5)(x-1)} =0; ; to ; ; left { {{x^2+5x-60=0} atop {xne -5,; xne 1}} right. \\D=25+240=265\\Otet:; ; x_1= frac{-5-sqrt{265}}{2} ; ;; ; x_2= frac{-5+sqrt{265}}{2}; .$

$2)quad frac{x}{x+1} + frac{x+2}{x+6} - frac{8-2x}{x^2+7x+6}=0\\x^2+7x+6=(x+1)(x+6)\\ frac{x(x+6)+(x+2)(x+1)-8+2x}{(x+1)(x+6)} =0\\ frac{x^2+6x+x^2+3x+2-8+2x}{(x+1)(x+6)} =0\\ frac{2x^2+11x-6}{(x+1)(x+6)} =0; ; to ; ; left { {{2x^2+11x-6=0} atop {xne -1; ,; xne -6}} right. \\D=121+48=169\\x_1= frac{-11-13}{4} =-6notin ODZ; ;; ; x_2= frac{-11+13}{4} =frac{1}{2}; .\\Otvet:; ; x=frac{1}{2}; .$