Question

Pешить урaвнение Х^4 - 12X^2+27=0

Answer 1

x^2=y

x^2-12x+27=0
d=36 
y1=(12+6)/2=9
y2=(12-6)/2=6
x^2=9  x1=+-3
x^2=6  x2= +-√6