Question

сократите дробь:
А) 2-√2/√6-√3
Б)x^2-2 /√2x + 2

Answer 1

2-√2/√6-√3=(2-√2)·(√6+√3)/(√6-√3)·(√6+√3)=

 ( 2 √6+2√3-√12-√6)/(√6²-√3²)=√6/3


x²-2/√2x+2=(x-√2)·(x+√2)/√2(x+√2)=(x-√2)/√2=(x√2-2)/2