Question

раскрыть скобки 502-(217-икс)=431;875-(икс+123)=379;(икс+11)+(23+икс)=212:икс+(икс+1)+(икс+2)=882

Answer 1

502-(217-х)=431 502-217+х=431 Х=431+217-502 Х=146 875-(х+123)=379 875-х-123=379 -х=379+123-875 -х=-313 Х=313 (х+11)+(23+х)=212 Х+11+23+х=212 2х=212-11-23 2х=178 Х=89 Х+(х+1)+(х+2)=882 Х+х+1+х+2=882 3х=882-2-1 3х=879 Х=293