Question

решите неравенство x^3-3×x^2-x+3 меньше или равно 0

Answer 1

$x^3-3x^2-x+3 leq 0 \ x^2(x-3)-(x-3) leq 0 \ (x-3)(x^2-1) leq 0 \ (x-3)(x-1)(x+1) leq 0 \ \ ---[-1]+++[1]---[3]+++ textgreater x \ \ OTBET: xin(- infty; -1] U [1;3]$