Question

2(x+3) (x-2)-(2x+1) (х-3)-7=0

Answer 1

2 (х^2-2х+3х-6)-(2х^2-6х+х-3)-7=0
2х^2-4х+6х-12-2х^2+6х-х+3-7=0
7х=16
х = 2 2/7