Question

cos 1110 * tg240 -sin810*ctg585 решить

Answer 1

cos(1080°+30°)*tg(180°+60°)-sin(720°+90°)*ctg(360°+225°)=cos30°*tg60°-sin90°*ctg(180°+45°)=(√3/2*√3)-(1*1)=3/2-1=1/2=0,5