Question

(y+4)(y+1)=y-(y-2)(2-y)

Answer 1

y квадрат+у+4у+4=у-(2y-y квадрат-4+2у)
y^2+5y+4=y-2y+y^2+4-2y
y^2-y^2+5y-3y=4-4
y=0