Question

Решите систему уравнений

(x+2)^2+(y-1)^2 = x^2+y^2+5

3*y+x = 28

Answer 1

(x+2)^2+(y-1)^2=x^2+y^2+5

3y+x=28

 

3y+x=28
x=-3y+28

 (x+2)^2+(y-1)^2=x^2+y^2+5

x^2+4x+4+y^2-2y+1-x^2-y^2-5=0

4x+5+y^2-2y-y^2-5=0

4x-2y=0
4*(-3y+28)-2y=0
 -14y+112=0

y=112/14

y=8

3y+x=28
3*8+x=28

x=4

Answer 2

(x+2)^2+(y-1)^2=x^2+y^2+5, 3*y+x=28

x = 4, y = 8;