Question

помогите решите 8,9,10,11 задания по химии

Answer 1

8.b. CH3COOMg+ H2
коэффициент ² перед кислотой

Answer 2

8) 2CH3-OH+2Na=2CH3ONA+ H2

   2CH3-COOH+2Mg=2CH3COOMg+H2

9)(C6H10O5)n+nH2O=>n/2 C12H22O11 

   n/2 C12H22O11 +nH2O=>nC6H12O6

CH3COOH+CH3OH->CH3C=O-OCH3

10)C3H5(OH)3+5O2=3CO2+4H2O

n(C3H5(OH)3)=18,4/92=0,2 моль

n(C3H5(OH)3): n(O2)

1:5

n(O2)=0,2*5=1моль

V(O2)=22,4*1=22.4

 

11)CH3COOH+CH3CH2OH->C2H5-O-C-(O)-CH3

m(CH3COOH)=100*1.05=105г

n(CH3COOH)=105/60=1,75 моль

n(CH3COOH):n(C2H5-O-C=O-CH3)

1:1

m(C2H5-O-C-(O)-CH3)=1.75*104=182