Question

(3m²-4)/8 - (2m+3)/12 = m/3 - 1/4

Answer 1

$frac{3m^2-4}{8} - frac{2m+3}{12} =frac {m}{3} - frac{1}{4}|*24\\3(3m^2-4) - 2(2m+3) =8m - 6\9m^2-12 - 4m-6 =8m - 6\9m^2-12 - 4m-6 -8m + 6=0\9m^2-12m-12=0|:3\3m^2-4m-4=0\D=(-4)^2-4*3*(-4)=16+48=64\\x_{1}=frac{4+8}{6}=frac{12}{6}=2\\x_{2}=frac{4-8}{6}=frac{-4}{6}=-frac{2}{3}$