Question

12*9^x-3^x-27=0 помогите пж

Answer 1

$12cdot9^x-3^x-27=0, \ 12cdot3^{2x}-3^x-27=0, \ 3^x=t, t textgreater 0, \ 12t^2-t-27=0, \ D=(-1)^2-4cdot12cdot(-27)=1+1296=1297, \ t_1=frac{1-sqrt{1297}}{24} textless 0, t_2=frac{1+sqrt{1297}}{24}, \ t=frac{1+sqrt{1297}}{24}, \ 3^x=frac{1+sqrt{1297}}{24}, \ x=log_3frac{1+sqrt{1297}}{24}$