Question

1). 2,4^(log2,4 10) - 1
2). log6 512 - log6 2
3) log8 16+ log8 4
4) log49log2 128
Срочно!!

Answer 1

1)2^4^(log(2,4)10)-1=10-1=9
2)log(6)512-log(6)2=log(6)(512/2)=log(6)256=8log(6)2
3)log(8)16+log(8)4=log(8)(16*4)=log(8)64=2
4)log(49)log(2)128)=log(49)7=1/2