Question

Решите уравнения: (4х+1)*(х+5)-(2х+1)*(2х-3)=58

Answer 1

$4x^{2} +20x+x+5-(4 x^{2} -6x+2x-3)=58 \ 4 x^{2} +21x+5-(4 x^{2} -4x-3)=58 \ 4 x^{2} +21x+5-4 x^{2} +4x+3=58 \ 25x+8=58 \ 25x=50 \ x=2$

Answer 2

Спасибо,большое)