Question

решите уравнение 3sin²x+4sinxcocx+5cos²x=2

Answer 1

$3sin^{2}x +4sinxcosx+5 cos^{2} x=2 sin^{2} x+2 cos^{2} x tg^{2}x+4tgx+3=0 tgx=-3; tgx=-1 x=-arctg3+ pi n; x=- pi /4 + pi k$
n,k прин. Z