Question

Помогите решить (фото)

Answer 1

1) 3^x(3^2-2*3)=3; 3^x=3/(9-6); 3^x=3/3; 3^x=1; x=0; 2)5^x(5^2-6*5)=-5; 5^x=-5/(25-30); 5^x=-5/-5; 5^x=1; x=0;

Answer 2

1) 3^x(3^2-2*3)=3; 3^x=3/(9-6); 3^x=3/3; 3^x=1; x=0; 2)5^x(5^2-6*5)=-5; 5^x=-5/(25-30); 5^x=-5/-5; 5^x=1; x=0;