Question

раскрыть скобки 4(n-2)(n-1) + (n-3)(n-2)(n-1)= 12(n+1)

Answer 1

(n2-n-2n+2)*4 + n2-2n-n-3n+6-3n+3+n2-n-2n+2 = 12n+12
4n2-4n+8n+8+4n2-12n+11=12n+12
8n2-8n+19=12n+12
8n2-8n-12n=12-19
8n2-20n=-7

Answer 2

как то так