Question

log2(4x-1)-log2(7x-3)=1

Answer 1

log2(4x-1)-log2(7x-3)=1
log2((4x-1)/(7x-3))=1
(4x-1)/(7x-3)=2^1
(4x-1)/(7x-3)=2
(4x-1-14x+6)/(7x-3)=0
4x-1-14x+6=0
-10x+5=0
x=1/2

Answer 2

log2(4x-1)-log2(7x-3)=1
log2(4x-1)/(7x-3)=log2(2)
(4x-1)/(7x-3)=2
4x-1=2(7x-3)
4x-1=14x-21
10x=20
x=2