Question

sin (-30°)-2atg(-45°)+cos(-60°)-ctg(-90°)

Answer 1

Sin (-30°)-2atg(-45°)+cos(-60°)-ctg(-90°)=3 * (-1) + 2* ctg° (-45°- 90°) - 2 * 0 - √3/2 = = 2 * ctg(-90°) - 0 - √3/2 = -2ctg 90° - √3/2 = -2 * 0 - √3/2 = -√3/2