Question

2(х+3)(х-2)-(2х+1)(х-3)-7=0

Answer 1

2(х+3)(х-2)-(2х+1)(х-3)-7=0
(2х+6)(х-2)-(2х^2-6х+х-3)-7=0
2х^2-4х+6х-12-(2х^2-5х-3)-7=0
2х^2-4х+6х-12х^2+5х+3-7=0
7х-16=0
Х=16/7=2 2/7